Formaldehyde when reacted with methyl magnesium bromide followed by hydrolysis gives

Options

A. `C_(2)H_(5)OH`
B. `CH_(3)COOH`
C. HCHO
D. `CH_(3)CHO`

Answer

To solve the problem of what product is formed when formaldehyde reacts with methyl magnesium bromide followed by hydrolysis, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Formaldehyde (HCHO)
- Methyl magnesium bromide (CH3MgBr)

### Step 2: Understand the Reaction
Methyl magnesium bromide is a Grignard reagent. Grignard reagents react with carbonyl compounds (like formaldehyde) to form alcohols.

### Step 3: Reaction of Formaldehyde with Methyl Magnesium Bromide
When formaldehyde reacts with methyl magnesium bromide, the nucleophilic carbon of the Grignard reagent (CH3-) attacks the electrophilic carbon of the carbonyl group in formaldehyde. This leads to the formation of an alkoxide intermediate.

The reaction can be represented as follows:
\[ \text{HCHO} + \text{CH}_3\text{MgBr} \rightarrow \text{H}_2\text{C(OMgBr)CH}_3 \]

### Step 4: Hydrolysis of the Alkoxide Intermediate
The next step is hydrolysis, where the alkoxide intermediate is treated with water (H2O). This process converts the alkoxide into an alcohol.

The hydrolysis can be represented as:
\[ \text{H}_2\text{C(OMgBr)CH}_3 + \text{H}_2\text{O} \rightarrow \text{H}_2\text{C(OH)CH}_3 + \text{Mg(OH)Br} \]

### Step 5: Identify the Final Product
The final product of this reaction is an alcohol. Specifically, the product formed is **2-propanol (isopropyl alcohol)**.

### Summary of the Reaction
1. Formaldehyde (HCHO) reacts with methyl magnesium bromide (CH3MgBr) to form an alkoxide.
2. Hydrolysis of the alkoxide leads to the formation of 2-propanol (isopropyl alcohol).

### Final Answer
The product formed when formaldehyde reacts with methyl magnesium bromide followed by hydrolysis is **2-propanol (isopropyl alcohol)**.

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