Reduction of cyclohex-2-enone with aluminium isopropoxide in excess of isopropyl alcohol with produce

Options

A. Cyclohexanol
B. Cyclohex-2-enol
C. Cyclohexanone
D. Benzene

Answer

To solve the question regarding the reduction of cyclohex-2-enone with aluminium isopropoxide in excess isopropyl alcohol, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The starting compound is cyclohex-2-enone, which has a structure of a cyclohexane ring with a ketone (C=O) group at the second position and a double bond (C=C) between the first and second carbon atoms.

2. **Understand the Reaction Conditions**:
- The reaction involves aluminium isopropoxide (Al(OPr)₃) as a reducing agent and isopropyl alcohol (IPA) in excess. This combination is known for reducing ketones and aldehydes to their corresponding alcohols.

3. **Recognize the Type of Reaction**:
- This reaction is classified as an MPV (Meerwein-Ponndorf-Verley) reduction. In this reaction, the ketone functional group will be reduced to an alcohol while the double bond in the cyclohexene remains intact.

4. **Perform the Reduction**:
- During the reduction, the carbonyl group (C=O) of cyclohex-2-enone will be converted to a hydroxyl group (C-OH), resulting in the formation of cyclohex-2-en-1-ol. The double bond in the cyclohexene will not be affected.

5. **Write the Final Product**:
- The final product after the reduction is cyclohex-2-en-1-ol. This compound retains the double bond from the original cyclohex-2-enone but now has an alcohol functional group.

### Final Answer:
The reduction of cyclohex-2-enone with aluminium isopropoxide in excess isopropyl alcohol produces cyclohex-2-en-1-ol.

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