`CH_(3)CH_(2)COONH_(4)overset(P_(2)O_(5))underset(Delta)toXoverset(H^(+)//H_(2)O)toY`.
Y and X respectively are

Options

A. `CH_(3)CH_(2)COOH,CH_(3)CH_(2)CN`
B. `CH_(3)CH_(2)CN,CH_(3)CH_(2)COOH`
C. `CH_(3)CH_(2)CH_(2)COOH,CH_(3)CH_(2)CH_(3)`
D. `CH_(3)CH_(3),CH_(3)CH_(2)COOCH_(3)`

Answer

To solve the problem, we will analyze the given reaction step by step.

### Step 1: Identify the starting compound
The starting compound is CH₃CH₂COONH₄, which is ammonium propionate.

### Step 2: Heating with P₂O₅
When ammonium propionate is heated in the presence of phosphorus pentoxide (P₂O₅), a dehydrating agent, it undergoes dehydration. The reaction removes a water molecule (H₂O) and converts the ammonium salt into an amide.

The reaction can be represented as:
\[ \text{CH}_3\text{CH}_2\text{COONH}_4 \xrightarrow{\Delta, P_2O_5} \text{CH}_3\text{CH}_2\text{CONH}_2 + \text{H}_2\text{O} \]

Here, CH₃CH₂CONH₂ is propanamide (an amide).

### Step 3: Identify compound X
After the dehydration step, we have formed propanamide (CH₃CH₂CONH₂). Therefore, X is:
\[ X = \text{CH}_3\text{CH}_2\text{CONH}_2 \]

### Step 4: Hydrolysis of X
Next, we perform hydrolysis of the amide (X) using H⁺ and H₂O. Hydrolysis of an amide typically results in the formation of a carboxylic acid and ammonia.

The reaction can be represented as:
\[ \text{CH}_3\text{CH}_2\text{CONH}_2 + H_2O \xrightarrow{H^+} \text{CH}_3\text{CH}_2\text{COOH} + \text{NH}_3 \]

Here, CH₃CH₂COOH is propanoic acid.

### Step 5: Identify compound Y
After hydrolysis, we have formed propanoic acid (CH₃CH₂COOH) and ammonia (NH₃). Therefore, Y is:
\[ Y = \text{CH}_3\text{CH}_2\text{COOH} \]

### Final Answer
Thus, the final answers are:
- X = CH₃CH₂CONH₂ (propanamide)
- Y = CH₃CH₂COOH (propanoic acid)