The product C of the reaction
`CH_(3)Cloverset(KCN)toAoverset(H_(2)O //H^(+))toBoverset(NH_(3))to`C is

Options

A. `HCONH_(2)`
B. `CH_(3)CN`
C. `CH_(3)CH_(2)NH_(2)`
D. `CH_(3)CONH_(2)`

Answer

To solve the problem step by step, we will analyze the reactions involved in the transformation from compound A to compound C.

### Step 1: Reaction of CH₃Cl with KCN
- **Reactants**: CH₃Cl (methyl chloride) and KCN (potassium cyanide).
- **Mechanism**: The cyanide ion (CN⁻) acts as a nucleophile and attacks the carbon atom in CH₃Cl, which is partially positive due to the electronegativity of chlorine. Chlorine, being a good leaving group, departs as Cl⁻.
- **Product**: The product formed is CH₃CN (methyl cyanide or acetonitrile).

### Step 2: Hydrolysis of CH₃CN
- **Reactant**: CH₃CN (methyl cyanide).
- **Conditions**: The reaction is carried out in the presence of water (H₂O) and an acid (H⁺).
- **Mechanism**: The triple bond in CH₃CN is hydrolyzed. The water molecule acts as a nucleophile, attacking the carbon atom of the nitrile group (C≡N). The reaction proceeds through the formation of an intermediate, leading to the formation of CH₃COOH (acetic acid) and NH₄⁺ (ammonium ion).
- **Product**: The product formed is CH₃COOH (acetic acid).

### Step 3: Reaction of CH₃COOH with NH₃
- **Reactants**: CH₃COOH (acetic acid) and NH₃ (ammonia).
- **Mechanism**: Ammonia reacts with acetic acid to form an amide. The reaction involves the nucleophilic attack of NH₃ on the carbonyl carbon of acetic acid, leading to the formation of CH₃CONH₂ (acetamide) and the release of a water molecule.
- **Product**: The final product formed is CH₃CONH₂ (acetamide).

### Final Product
The final product C of the reaction sequence is **CH₃CONH₂ (acetamide)**.

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