A polypeptide on complete hydrolysis gives three amino acids. How many sequences are possible for A polypeptide on complete hydrolysis gives three amino acids. How many sequences are possible for that polypeptide?

Options

A. 1
B. 3
C. 6
D. 9

Answer

To determine how many sequences are possible for a polypeptide that consists of three different amino acids, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Number of Amino Acids**:
We have three different amino acids. Let's denote them as A, B, and C.

2. **Understand the Concept of Permutations**:
The number of different sequences (or arrangements) of a set of items can be calculated using permutations. For n distinct items, the number of permutations is given by n! (n factorial).

3. **Calculate the Factorial**:
Since we have 3 amino acids, we need to calculate 3! (3 factorial):
\[ 3! = 3 \times 2 \times 1 = 6 \]

4. **List the Possible Sequences**:
The possible sequences of the three amino acids A, B, and C are:
- ABC
- ACB
- BAC
- BCA
- CAB
- CBA

5. **Conclusion**:
Therefore, the total number of different sequences possible for the polypeptide made up of three amino acids is 6.

### Final Answer:
The number of sequences possible for the polypeptide is **6**.

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