(int_(0)^(1)(1-x^(50))^(100)dx)/(int_(0)^(1)(1-x^(50))^(101)dx)=(5051)/(K(5050))" then "K" is "

Evaluate: 5050(int_(0)^(1)(1-x^(50))^(100)dx)/(int_(0)^(1)(1-x^(50))^(101)dx)

Evaluate: 5050(int_0^1(1-x^(50))^(100)dx)/(int_0^1(1-x^(50))^(101)dx)

Evaluate: 5050(int0 1(1-x^(50))^(100)dx)/(int0 1(1-x^(50))^(101)dx)

Evaluate: 5050(int0 1(1-x^(50))^(100)dx)/(int0 1(1-x^(50))^(101)dx)

Evaluate: 5050(int0 1(1-x^(50))^(100)dx)/(int0 1(1-x^(50))^(101)dx)

The value of ((5050)int_(0)^(1)(1-x^(50))^(100)dx)/(int_(0)^(1)(1-x^(50))^(101)dx) is

The vlaue of ((5050)int_(0)^(1)(1-x^(50))^(100)dx)/(int_(0)^(1) (1-x^(50))^(100)dx) , is

If I_(1)=int_(0)^(1)(1-x^(50))^(100)dx and I_(2)=int_(0)^(1)(1-x^(50))^(101)dx, If I_(2)=(alpha)/(beta)I_(1) ( alpha,beta are coprime) then beta-alpha