A reaction `S_(8)(g) hArr 4S_(2)(g)` is carried out by taking `2` mol of `S_(8)(g)` and `0.2` mol of `S_(2)(g)` is a reaction vessel of `1 L`. Which one is not correct if `K_(c)=6.30xx10^(-6)`

A reaction S_((g)) hArr 4S_(2(g)) is s carried out by taking 2 moles of S_(8(g)) and 0.2 mole of S_(2(g)) in a reaction vessel of l lit. Which one is not correct. If K_(c) = 6.3 xx 10^(-6) .

A reaction S_(8)(g) Leftrightarrow 4S_(2)(g) is carried out by taking 2 mol of S_(g(g)) and 0.2 mol of S_(2(g)) is a reaction vessel of 1 L and K=6.30 xx 10^(-6) then (a) Reaction qutient is 8 xx 10^(-4) b) Reaction proceeds in backward direction c) Reaction proceeds in forward direction The correct options are

At a given temperature, K_c=6.3xx10^(-6) for the reaction S_8(g)hArr4S_2(g) . At the same temperature, if the reaction is started with 2 moles of S_8(g) and 0.2 mol of S_2(g) in a closed vessel of volume 1L, then which of the following comments are true regarding this reaction-

An equilibrium mixture for the reaction, 2H_(2)S(g) hArr 2H_(2) (g) + S_(2) (g) has 1 mole of H_(2) S, 0.2 mole of H_(2) and 0.8 mole of S_(2) in 2 L flask . The value of K_(C) in mol L^(-1) is

The reaction A(g)+4B(g)hArr2C(g)+3D(g) is carried out in a closed vessel of volume 2L by taking 3 mol of A(g) and 4 mol of B(g ). At equilibrium, if the amount of C(g) be 1 mol. then K_c for the reaction is-

At 1400 K, K_( c) = 2.5 xx 10^(-3) for the reaction CH_(4)(g)+2H_(2)S(g)hArrCS_(2)(g)+4H_(2)(g) A 10 L reaction vessel at 1400 K contains 2.0 mol of CH_(4) , 3.0 mol of CS_(2) , 3.0 mol of H_(2)S . In which direction does the reaction proceed to reach equilibrium?

An equilibrium mixture for the reaction 2H_2S(g) hArr 2H_2(g)+S_2(g) had 1 mole of hydrogen sulphide, 0.2 mole of H_2 and 0.8 mole of S_2 in 2 litre vessel. The value of K_c is:

Calculate K_(c) for the reaction: 2H_(2)(g)+S_(2)(g) hArr 2H_(2)S(g) if 1.58 mol H_(2)S, 1.27 mol H_(2) and 2.78xx10^(-6) mol of S_(2) are in equilibrium in a flask of capacity 180 L at 750^(@)C .