[4],[5],[(53)/(4)]quad (3cos theta+cos3 theta)/(3sin theta-sin3 theta)=

(3sin theta-sin3 theta)/(3cos theta+cos3 theta)=

4 sin 5 theta cos 3 theta sin 2 theta

sin4 theta-sin2 theta=cos3 theta

(sin3 theta+cos3 theta)/(cos theta-sin theta)=1+2xx sin2 theta

Prove that (cos^3 theta -cos 3 theta)/(cos theta)+ (sin^3 theta+sin3 theta)/(sin theta)=3 .

Solve sqrt(3)cos theta-3sin theta=4sin2 theta cos3 theta

Express the following in a+ib form: ((cos2 theta-i sin2 theta)^(4)(cos4 theta+i sin4 theta)^(-5))/((cos3 theta+i sin3 theta)^(-2)(cos3 theta-i sin3 theta)^(-9))

(cos4 theta+cos3 theta+cos2 theta)/(sin4 theta+sin3 theta+sin2 theta)=cot3 theta

Prove that : (cos4 theta+cos3 theta+cos2 theta)/(sin4 theta+sin3 theta+sin2 theta)=cot3 theta

cos^(3)theta sin 3theta + sin^(3)theta cos3theta=3/4