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Complete the following nuclear equation ...

Complete the following nuclear equation by suppling the symbol for the other product of the fission :
`._(92)^(235)U+_(0)^(1)n rarr _(38)^(94)Sr +………+2_(0)^(1)n`

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The product P of the nuclear reaction ""_(92)^(235)U+""_(0)^(1)n to P +""_(36)^(92)Kr +3""_(0)^(1)n is

Fill in the blank ""_(92)U^(235) +""_(0)n^(1) to ? +""_(36)^(92)Kr + 3""_(0)^(1)n

Fill in the blank ""_(92)U^(235) +""_(0)n^(1) to ? +""_(36)^(92)Kr + 3""_(0)^(1)n

Rewrite and complete the following nuclear reaction by filling in the atomic number of Ba and mass number of Kr : ""_(92)^(235)U+""_(0)^(1)nto""_(...)^(144)Ba+""_(36)^(...)Kr+3""_(0)^(1)n+"Energy"

Calculate the energy released in the following nuclear reaction and hence calculate the energy released when 235 gram of uranium-235 undergoes fission. U_(92)^(235) + n_(0)^(1) to Kr_(36)^(92) + Ba_(56)^(141) + 3n_(0)^(1) Rest masses of U^(235), Ba^(141) ,Kr^(92) and neutron are 235.04390 amu, 140.91390 amu, 91.89730 amu and 1.00867 amu respectively. Avogadro number = 6.023 xx 10^(23) .