One ticket is selected at random from 100 tickets numbered 00,01,02,...,98,99. If `x_1, a n dx_2` denotes the sum and product of the digits on the tickets, then `P(x_1=9//x_2=0)` is equal to `2//19` b. `19//100` c. `1//50` d. none of these

One ticket is selected at random from 100 tickets numbered 00, 01, 02,.., 99. Suppose A and B are the sum and product of the digit found on the ticket. Then P(A=7//B=0) is given by

One ticket is selected at random from 100 tickets numbered 00,01,02, …, 99. Suppose A and B are the sum and product of the digit found on the ticket, respectively. Then P((A=7)//(B=0)) is given by

One ticket is selected randomly from the set of 100 tickets numbered as {00,01,02,03,04,05......98,99}E_(1), and E_(2), denote the sum and product of the digits of the number of the selected ticket. The value of P((E_(1)=9)/(E-2=0)) is

One ticket is selected at ransom form 50 tickets numbered 00,01,02,…,49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, is

One ticket is selected at random from 50 tickets numbered 00, 01, 02, ... , 49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals (1) 1/14 (2) 1/7 (3) 5/14 (4) 1/50

One ticket is drawn from a box containing 100 tickets numbered from 1 to 100. If the number on the selected ticket is x then probability that x+ 1/x gt 2 is

Out of 2n tickets numbered 1,2,......,2n three are chosen at random.The probability that the numbers on them are in A.P.is

100 tickets are numbered as 00,01,02)...0910,11,12,....99 out of them one ticket is drawn at random.The probability that the sum of the digits of the number on the ticket is 9 is