Resistance of a decimolar solution between two electrodes 0.02 meter apart and 0.0004 `m^2` in area was found to be 50 ohm. Specific conductance (k0 is :

Resistance of a decimolar solution between two electrodes 0.02 meter apart and 0.0004m^(2) in area was fround to be 50 ohm . Specific conductance (k) is :

The resistance of solution of salt occupying a volume of between two platinum electrodes 1.8 cm apart and 5.4 cm^(2) in area was found to be 32 ohms. Calculate the conductivity of the solution.

The resistance of decinormal solution of a salt occupying a volume between two platinum electrodes 1.80 cm apart and 5.4 cm^(2) area was found to be 32 ohm . Calculate k and wedge _(eq) .

The resistance of decinormal solution of a salt occupying a volume between two platinum electrodes 1.80 cm apart and 5.4 cm^(2) area was found to be 32 ohm . Calculate k and wedge _(eq) .

The resistance of decinormal solution of a salt occupying a volume between two platinum electrodes 1.80 cm apart and 5.4 cm^(2) area was found to be 32 ohm . Calculate k and wedge _(eq) .

The resistance of solution of a salt occupying a volume between two platinum electrode 1.8cm apart and 5.4cm^(2) in area was found to be 30 ohm. Calculate the conductivity of the solutions.

The resistance of a decinormal solution of a salt occupying a volume between two platinum electrodes which are 1.80 cm apart and 5.4 cm^(2) in area was found to be 50 omega calculate the equilvalent conductance of the solution

The resistance of a 0.5 M solution of an electrolyte enclosed between two platinum electrodes 1.5 cm apart and having an area of 2*0cm^(3) was found to be 30 ohm. Calculate the molar conductivity of the electrolyte.

1.0 N solution of a salt surrounding two platinum electrodes 2.1 cm apart and 4.2 sq cm in area was found to offer a resistance of 50 ohm. Calculate the equivalent conductivity of the solution.