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The mean square deviation about -1 and 1 of a set of observations are 7 and 3 respectively then standard deviation of the set is

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The mean square deviation of a set of observation x_(1), x_(2)……x_(n) about a point m is defined as (1)/(n)Sigma_(i=1)^(n)(x_(i)-m)^(2) . If the mean square deviation about -1 and 1 of a set of observation are 7 and 3 respectively. The standard deviation of those observations is

The mean square deviation of a set of observation x_(1), x_(2)……x_(n) about a point m is defined as (1)/(n)Sigma_(i=1)^(n)(x_(i)-m)^(2) . If the mean square deviation about -1 and 1 of a set of observation are 7 and 3 respectively. The standard deviation of those observations is

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If mean of squares of deviations of a set of n observations about -2a n d2 are 18 and 10 respectively then standard deviation of this set of observations is 3 (b) 2 (c) 1 (d) None of these

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If mean of squares of deviations of a set of n observations about -2 and 2 are 18 and 10 respectively then standard deviation of this set of observations is 3 (b) 2 (c) 1 (d) None of these

If mean of squares of deviations of a set of n observations about - 2 and 2 are 18 and 10 respectively,then standard deviation of this set of observations is

The mean square deviation of a set of m observations y_1, y_2…..y_m about a point K is defined as 1/m sum_(i = 1)^(m) (y_i - k)^(2) . The mean square deviation about -3 and 3 are 16 and 8 respectively, then standard deviation of this set of observation?