Home
Class 12
MATHS
If the area enclosed between the curves ...

If the area enclosed between the curves `y=kx^2` and `x=ky^2`, where `kgt0`, is 1 square unit. Then k is: (a) `1/sqrt(3)` (b) `sqrt(3)/2` (c) `2/sqrt(3)` (d) `sqrt(3)`

A

`1/sqrt3`

B

`2/sqrt3`

C

`sqrt3/2`

D

`sqrt3`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

If the area enclosed between the curves y=kx^(2) and x=ky^(2), where k>0, is 1 square unit.Then k is: (a) (1)/(sqrt(3)) (b) (sqrt(3))/(2) (c) (2)/(sqrt(3))(d)sqrt(3)

The area enclosed between the curves y = x^(3) and y = sqrt(x) is

The area enclosed between the curves y=ax^(2) and x=ay^(2)(a>0) is 1 sq.unit, value of a is (1)/(sqrt(3)) (b) (1)/(2)(c)1(d)(1)/(3)

Area bounded between the curves y=sqrt(4-x^(2)) and y^2=3|x| in square units is

The rationalisation factor of sqrt(3) is -sqrt(3) (b) (1)/(sqrt(3))(c)2sqrt(3)(d)-2sqrt(3)

The rationalisation factor of 2+sqrt(3) is 2-sqrt(3) (b) sqrt(2)+3(c)sqrt(2)-3(d)sqrt(3)-2

The area bounded by the curve x^(2)=ky,k>0 and the line y=3 is 12unit^(2) . Then k is (A)3(B)3sqrt(3)(C)(3)/(4) (D) none of these

The length of the chord of the parabola y^(2)=x which is bisected at the point (2,1) is (a) 2sqrt(3)( b) 4sqrt(3)(c)3sqrt(2) (d) 2sqrt(5)

The area enclosed by the curve y=sin x+cos x and y=|cos x-sin x| over the interval [0,(pi)/(2)] is 4(sqrt(2)-2) (b) 2sqrt(2)(sqrt(2)-1)2(sqrt(2)+1)(d)2sqrt(2)(sqrt(2)+1)