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Portion of asymptote of hyperbola x^2/a^...

Portion of asymptote of hyperbola `x^2/a^2-y^2/b^2 = 1` (between centre and the tangent at vertex) in the first quadrant is cut by the line `y + lambda(x-a)=0` (lambda is a parameter) then (A) `lambda in R` (B) `lambda in (0,oo)` (C) `lambda in (-oo,0)` (D) `lambda in R-{0}`

A

`lambda in R`

B

`lambda in (0, oo)`

C

`lambda in (-oo, 0)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B


The line `y+lambda(x-a)=0` will intersect the portion of the asymptote in the first quadrant only if its slope is negative.
Hence,
`-lambda lt 0`
`"or "lambda gt 0`
`therefore" "lambda in (0, oo)`
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