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From the point (2, 2) tangent are drawn ...

From the point (2, 2) tangent are drawn to the hyperbola `(x^2)/(16)-(y^2)/9=1.` Then the point of contact lies in the first quadrant (b) second quadrant third quadrant (d) fourth quadrant

A

first quadrant

B

second quadrant

C

third quadrant

D

forth quadrant

Text Solution

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The correct Answer is:
C, D
The equations of asymptotes are `4y-3x=0 and 4y+3x=0`

As point (2, 2) lies above the asymptote, the points of contact of the tangents are in the third and fourth quadrants.
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