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Draw the graph of y=sin^(-1)x+cos^(-1)x....

Draw the graph of `y=sin^(-1)x+cos^(-1)x.`

Text Solution

Verified by Experts

We have `y = g(x)=sin^(-1)x+cos^(-1)x, x in [-1, 1)`
`=pi/2`
So the graph of `y=f(x)" is the line "y=pi/2" for "x in [-1, 1]`
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