The value of `tan^(-1).(4)/(7) + tan^(-1).(4)/(19) + tan^(-1).(4)/(39) + tan^(-1).(4)/(67) ... oo` equals

Options

A. `tan^(-1) 1 + tan^(-1).(1)/(2) + tan^(-1).(1)/(3)`
B. `tan^(-1) 1 + cot^(-1) 3`
`cot^(-1) + cot^(-1).(1)/(2) + cot^(-1).(1)/(3)`
C. `cot^(-1) 1 + cot^(-1).(1)/(2) + cot^(-1).(1)/(3)`
D. `cot^(-1) 1 + tan^(-1) 3`

Answer

B

Explanation

Let us find the value of general term of the series
`S = 7 + 19 + 39 + 67 + .. + T_(n)`
`(S = " " 7 + 19 + 39 +.. + T_(n-1) + T_(n))/(0 = 7 + 12 + 20 + 28 + ...(n "terms") -T_(n))` (subtracting)
`:. T_(n) = 7 + ((n -1))/(2) [24 + 8 (n-2)] = 4n^(2) + 3`
`:. T_(n) = tan^(-1).(4)/(4n^(2) + 3) = tan^(-1).(1)/(n^(2) + (3)/(4))`
`= tan^(-1).(1)/(1 + (n^(2) -(1)/(4)))`
`= tan^(-1) [((n+ (1)/(2)) - (n-(1)/(2)))/(1+(n+(1)/(2)) (n-(1)/(2)))]`
`= tan^(-1) (n+(1)/(2)) - tan^(-1) (n -(1)/(2))`
Hence,
`:. S_(n) = underset(r=1)overset(n)sum T_(r) = tan^(-1) (n + (1)/(2)) - tan^(-1).(1)/(2)`
`:. S_(n) = tan^(-1) oo - tan^(-1).(1)/(2)`
`= (pi)/(2) - tan^(-1).(1)/(2)`
`= tan^(-1) 1 + cot^(-1) 3`