If `270^@ < theta < 360^@`, then `sqrt(2 + sqrt(2 + 2 cos theta))` is equal to

Find the trignometric functions of: -270^@

Answer the following:Find the trignometric funtions of: 270^@

An angle measuring 270^(@) is

An angle measuring 270^(@) is

The value of [cos (270^(@) +theta)cos (90^(@) -theta)-sin (270^(@) -theta)cos theta) is-

Prove: (iii) "sec" (270^(@) - theta) "sec" (90^(@)- theta) - tan (270^@ - theta) tan (90^(@) + theta) = -1

Prove that cos theta + "sin " (270^(@) +theta) - "sin "(270^(@) -theta) + "cos " (180^(@) +theta) =0

Simplify the following : sin(90^@+ theta) tan (270^@ +theta) cot (90^@+theta) cosec (270^@+theta) .

The value of cos (270^(@) + theta) cos ( 90^(@) -theta) -sin (270^(@) - theta) cos theta is