Two metal sphere of same mass are suspended form a common point by a light insulating string.The length of each string is same.The sphere are given electric charges `+q` on one end and `+4q` on the other.Which of the following diagram best shows the resulting positons of spheres?

Two metal sphers of masses m_(1) and m_(2) are suspended from a common point by a light insulting strings of same length. The length of each string is same. The spheres are given positive charges q_(1) and q_(2) . Figure A shows angles made by the strings with vertical are different where as for figure B same. Then, which of the following is possible

Two spheres, each having mass m are suspended from a common point by two insulating strings of length l. The spheres are identically charged and the separation between the spheres is 'd' . Find the charge on each sphere.

Two small spheres, each having a mass of 20 g, are suspended form a common point by two insulating strings of length 40 cm each. The spheres are identically charged and the speration between the balls at equilibrium is found to be 4 cm . Find the charge on each sphere.

Two small spheres, each having a mass of 20 g, are suspended form a common point by two insulating strings of length 40 cm each. The spheres are identically charged and the speration between the balls at equilibrium is found to be 4 cm . Find the charge on each sphere.

Two small spheres, each having a mass of 20 g, are suspended form a common point by two insulating strings of length 40 cm each. The spheres are identically charged and the speration between the balls at equilibrium is found to be 4 cm . Find the charge on each sphere.

Three identically charged, small spheres each of mass m are suspended from a common point by insulated light strings each of length I. The spheres are always on vertices of an equilateral triangle of length of the sides x (ltlt l) . Calculate the rate dq/ dt with which charge on each sphere increases if length of the sides of the equilateral triangle increases slowly according to law (dx)/(dt)=(a)/(sqrt(x))