If `3 sin beta=sin(2alpha+beta)`, then `tan (alpha+beta)-2 tan alpha` is

If 3sin beta = sin(2alpha + beta) , then tan(alpha + beta)-2tan alpha is:

If sin beta=sin(2alpha+beta) , then tan(alpha+beta)-2tan alpha is

If 3sin beta=sin(2 alpha+beta) then tan(alpha+beta)-2tan alpha is (a)independent of alpha (bindependent of beta (c)dependent of both alpha and beta( d)independent of both alpha and beta

If sin (alpha+beta)=1, sin (alpha-beta)=1/2 , then tan (alpha+ 2beta). tan (2 alpha+beta) is equal to :

If sin beta = 1/5 sin(2alpha +beta) , show that tan(alpha +beta) = 3/2 tan alpha .

If sin (alpha + beta)=1, sin (alpha- beta)= (1)/(2) , then tan (alpha + 2beta) tan (2alpha + beta) =

If 3 sin alpha=5 sin beta , then (tan((alpha+beta)/2))/(tan ((alpha-beta)/2))=

If 3 sin alpha=5 sin beta , then (tan((alpha+beta)/2))/(tan ((alpha-beta)/2))=