In a radioactive material the activity at time `t_(1)` is `R_(1)` and at a later time `t_(2)`, it is `R_(2)`. If the decay constant of the material is `lambda`, then

In a radioactive material the activity at time t_1 is R_1 and at a later time t_2 , it is R_1 . If the decay constant of the material is lamda , then

The activity of a radioactive substance is R_(1) at time t_(1) and R_(2) at time t_(2)(gt t_(1)) . Its decay cosntant is lambda . Then .

The activity of a radioactive substance is R_(1) at time t_(1) and R_(2) at time t_(2)(gt t_(1)) . Its decay cosntant is lambda . Then .

The rate of decay of a radioactive sampel is given by R_(1) at time t_(1) and R_(2) at a later time. t_(2) . The mean life of this radioactive sample is:

Half-life of a radioactive substance is T. At time t_1 activity of a radioactive substance is R_1 and at time t_2 it is R_2 . Find the number of nuclei decayed in this interval of time.

Half-life of a radioactive substance is T. At time t_1 activity of a radioactive substance is R_1 and at time t_2 it is R_2 . Find the number of nuclei decayed in this interval of time.

The rate of decay of a radioactive species is given by R_(1) at time t_(1) and R_(2) at later time t_(2) . The mean life of this radioactive species is:

The activity of a radioactive susbtance is R_(1) at time t_(1) and R_(2) at time t_(2) (>t1). its decay constant is λ. Then, number of atoms decayed between time interval t_(1) and t_(2) are

The activity of a radioactive substance is R_(0) at t = 0 , R_(1) at t = t and R_(2) at t = 2t . The decay constant of this species is/are given by:

Four thousand active nuclei of a radioactive material are present at t= 0. After 60 minutes 500 active nuclei are left in the sample. The decay constant of the sample is