The composite mapping fog of the maps `f:R to R , f(x)=sin x and g:R to R, g(x)=x^(2)`, is

The composite mapping fog of the maps f:RtoR,f(x)=sinx,g:RtoR,g(x)=x^(2) is :

Let :R rarr R;f(x)=sin x and g:R rarr Rg(x)=x^(2) find fog and gof.

Let : R->R ; f(x)=sinx and g: R->R ; g(x)=x^2 find fog and gof .

Let R be the set of real numbers. If f: R to R ;f(x)=x^2 and g: R to R ;g(x)=2x+1 . Then, find fog and gof . Also, show that fog!=gofdot

A mapping R defined on the set of real numbers such that f(x)=sin x,x in R and g(x)=x^(2)x in R prove that gof!= fog

Let R be the set of real number and the mapping f :R to R and g : R to R be defined by f (x)=5-x^(2)and g (x)=3x-4, then the value of (fog) (-1) is

Let R be the set of real number and the mapping f :R to R and g : R to R be defined by f (x)=5-x^(2)and g (x)=3x-4, then the value of (fog) (-1) is

If f:R rarr R and g:R rarr R given by f(x)=x-5 and g(x)=x^(2)-1, Find fog