A party consisting of 5 boys and 10 girls is divided at random into five groups of three persons each.The chance that each group will have one boy is `(81/n)` where `n in N` is divisible by

10 boys and 2 girls are divided into 3 groups of 4 each.The probability that the girls will be in different groups is

6 boys and 6 girls are randomly divided into two equal groups. Find the probability that each group contains same number of boys and girls.

A class consists of 10 boys and 8 girls. Three students are selected at random. Find the probability that the selected group has : 2 boys and 1 girl.

A class consists of 10 boys and 8 girls. Three students are selected at random. Find the probability that the selected group has : all Boys.

A class consists of 10 boys and 8 girls. Three students are selected at random. Find the probability that the selected group has : all girls.

A group of 2n boys and 2n girls is randomly divided into two equal groups.The probability that each group contains the same number of boys and girls is (A) 1/2 (B) 1/n (c) 1/2n (D) None of these

A group consists of 7 boys and 5 girls . Find the number of ways in which a team of 5 members can be selected so as to have atleast one boy and girl.

A group of 4 boys and 3 girls are arranged at random , one after the other. Probability that girls and boys occupy alternate seats is ,