Water is filled in a container upto height 3m. A small hole of area 'a' is punched in the wall of the container at a height 52.5 cm from the bottom. The cross sectional area of the container is A. If `a//A=0.1` then `v^2` is (where v is the velocity of water coming out of the hole)

Oil is filled in a cylindrical container up to height 4m. A small hole of area 'p' is punched in the wall of the container at a height 1.52m from the bottom. The cross sectional area of the container is Q. If p/q = 0.1 then v is (where vis the velocity of oil coming out of the hole)

A liquid is filled in a container to a height H. A small hole is opened in the side of the container a height h below the surface of the liquid. The distance L from the bottom of the container of the point where the stream of liquid leaving the container meets the ground is :

A tank of height 15 m and cross-section area 10 m^(2) is filled with water. There is a small hole of cross-section area a which is much smaller than the container, located at a height of 12 m from the base of the container. How much force should be applied with coming out of the top level, so that water coming out of the holwe hits the ground at a distance of 16 m? ("Take of water =1000 kg m"^(-3))

Water is filled in a cylindrical container to a height of 3m . The ratio of the cross-sectional area of the orifice and the beaker is 0.1 . The square of the speed of the liquid coming out from the orifice is (g=10m//s^(2)) .

Water is filled in a cylindrical container to a height of 3m . The ratio of the cross-sectional area of the orifice and the beaker is 0.1 . The square of the speed of the liquid coming out from the orifice is (g=10m//s^(2)) .

Water is filled in a cylindrical container to a height of 3m . The ratio of the cross-sectional area of the orifice and the beaker is 0.1 . The square of the speed of the liquid coming out from the orifice is (g=10m//s^(2)) .

What is filled in a cylindrical container to a height of 3 m . The ratio of the cross-sectional area of the orifice and the beaker is 0.1 . The square of the speed of the liquid coming out from the orifice is (g = 10 m//s^2) .