If `2x+y-z=5, 3x-2y+2z=-3` and `x-3y-3z=-2` then the value of `y` satisfying the system of equation is

if 2x+3y-3z=0;5x-2y+2z=19;x+7y-5z=5. Then the value of x+y-z is

If alpha,beta and gamma are the values of x,y and z respectively which satisfy the system of equations 2x+y+z=1,x-2y-3z=1 and 3x+2y+4z=5, then sin^(-1)((alpha)/(gamma))=

2x+3y+3z=5 x-2y+z=-4 3x-y-2z=3

Statement - I The soluton of the system of equations 2x-y+3z=9,x+y+z=6,x-y+z=2 is x=1,y=2,z=3 Statement - II : The solution of the system of equations x+2y-z=3,3x=y+2z=1 , 2x-2y+3z=2 is x=-1,y=4,z=4 Which of the above Statement(s) is true ?

For the system of equations 3x+y=1,x-2y=5 and x-y+3z+3=0, the value of z is

x+y+z=1 x-2y+3z=2 5x-3y+z=3

The equations x+2y-z=3, 3x-y+2z=1, 2x-2y+3z=2 have

By crammer's rule ,if the values of x,y and z which satisfy the system of equations x+y+z=2, x+2y+3z=1 ,and 3x+y-5z=4 are respectively L,M and N, then 3L+5M+N=

By crammer's rule,if the values of x,y and z which satisfy the system of equations x+y+z=2 ,x+2y+3z=1 ,and 3x+y-5z=4 are respectively L,M and N then 3L +5M+N=