`cos2x-cos8x+cos6x=1`

Prove that: 1+cos2x+cos4x+cos6x=4cos x cos2x cos3x

If f(x)=cos x cos2x cos4x cos8x cos16x then

Prove that 1+cos2x+cos4x+cos6x =4cosx cos 2x cos 3x

The value of int_( sin )x cos x cos2x cos4x cos8x cos16x)dx is int(sin x cos x cos2x cos4x cos8x cos16x)dx is equal to

If f(x)=cos x cos2x cos4x cos8x cos16x then f'((pi)/(4)) equals

Prove that 1+cos2x+cos4x+cos6x=4cosxcos2xcos3x .

Prove that: 1+cos2x+cos4x+cos6x=4cosxcos2xcos3x

int sin x*cos x*cos2x*cos4x*cos8x*cos16xdx=

prove that cos x cos2x cos4x cos8x=(sin16x)/(16sin x)

=(3)/(5)lim_(x rarr0)((1-cos2x*cos4x*cos6x*cos8x*cos10x)/(x^(2)))