Home
Class 12
MATHS
The equation of the circle drawn with th...

The equation of the circle drawn with the focus of the parabola `(x - 1)^2 - 8 y = 0` as its centre touching the parabola at its vertex is:

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of the circle drawn with the focus of the parabola (x – 1)^(2) - 8y = 0 as its centre and touching the parabola at its vertex is

The equation of the circle drawn with the focus of the parabola (x-1)^(2)-8y=0 as its centre touching the parabola at its vertex is:

If a circle drawn with radius 1 unit and whose centre is the focus of the parabola y^(2)=4x touches the parabola at

Let a circle touches to the directrix of a parabola y ^(2) = 2ax has its centre coinciding with the focus of the parabola. Then the point of intersection of the parabola and circle is

Let a circle touches to the directrix of a parabola y ^(2) = 2ax has its centre coinciding with the focus of the parabola. Then the point of intersection of the parabola and circle is

Let the directrix of a parabola y^(2)=2 a x is a tangent to a circle which has its centre coinciding with the focus of the parabola. Then the point of intersection of the parabola and circle is/are

Equation of a circle which touches the parabola y^(2)-4x+8=0, at (3,2) and passes through its focus is

The equation of the parabola with its vertex at (1, 1) and focus at (3, 1) is