Home
Class 12
CHEMISTRY
The EMF of a galvanic cell Pt|H(2)(1 atm...

The `EMF` of a galvanic cell `Pt|H_(2)(1 atm)|HCl(1M)|Cl_(2)(g)|Pt` is `1.29V`. Calculate the partial pressure of` Cl_(2)(g)`. `E^(c-)._(Cl_(2)|Cl^(c-))=1.36V`.

Promotional Banner

Similar Questions

Explore conceptually related problems

The EMF of the cell Pt,Cl_(2(g))(P_(1)atm)|Cl_((aq))^(-)(1M)|Cl_(2(g)))P_(2)Atm) , Pt will be positive when :

Calculate single electrode potential of Pt, Cl_(2)//Cl^(-) (0.01)(E^(@)= +1.36V)

Write the cell reaction of the given galvanic cell : Pt|H_(2)"(g, 1atm)"|HCl(aq)|Hg_(2)Cl_(2)|Hg|Pt

Calculate the electrode potential of given electrode Pt, Cl_(2) (1.5 bar) 2Cl^(-) (0.01M), E_(Cl_(2)//2Cl^(-))^(@) = 1.36V

Calculate the electrode potential of given electrode Pt, Cl_(2) (1.5 bar) 2Cl^(-) (0.01M), E_(Cl_(2)//2Cl^(-))^(@) = 1.36V

Pt(Cl_(2))(p_(1))|HCl(0.1M)|(Cl_(2))(p_(2)),Pt cell reaction will be endergonic if

Pt(Cl_(2))(p_(1))|HCl(0.1M)|(Cl_(2))(p_(2)),Pt cell reaction will be endergonic if

Pt(Cl_(2))(p_(1))|HCl(0.1M)|(Cl_(2))(p_(2)),Pt cell reaction will be endergonic if