Theorem 6.8 : In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Pythagoras theorem (Baudha-yana theorem): In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Prove that in a right triangle, the square of the hypotenure is equal to the sum of the squares of the others two sides.

Prove that in a right traiangle, the square of the hypotemuse is equal to the sum of the squares of the other two sides.

Prove that "In a right triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides".

Prove that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. Use the above theorem, in the following. If ABC is an equilateral triangle with AD bot BC , then prove that AD^(2) = 3DC^(2) .

Prove that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

(Pythagoras's Theorem) Prove by vector method that in a right angled triangle,the square of the hypotenuse is equal to the sum of the squares of the other two sides.

(Pythagorass Theorem) Prove by vector method that in a right angled triangle,the square of the hypotenuse is equal to the sum of the squares of the other two sides.

(Pythagoras's Theorem) Prove by vector method that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

(Pythagoras's Theorem) Prove by vector method that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.