in `DeltaABC , (s-a)/Delta = 1/8 ,(s-b)/Delta = 1/12 ,(s-c)/Delta = 1/24` then `b=`

In a triangle ABC,(s-a)/Delta=1/8,(s-b)/Delta=1/12,(s-c)/Delta=1/24 then b=

In triangleABC," if"(s-a)/(Delta)=1/8, (s-b)/(Delta)=1/12 and (s-c)/(Delta)=1/24 , then b=

In triangleABC," if"(s-a)/(Delta)=1/8, (s-b)/(Delta)=1/12 and (s-c)/(Delta)=1/24 , then b=

Delta ABC,(s-a)/(Delta)=(1)/(8),(s-b)/(Delta)=(1)/(12),(s-c)/(Delta)=(1)/(24) then b=

In Delta ABC ( ( s-a))/( Delta) = (1)/( 8) , ( ( s-b))/( Delta ) = (1)/(12), ((s-c))/( Delta ) =(1)/( 24) then b =

If p_1,\ p_2,\ p_3 are the altitudes of a triangle from its vertices A ,\ B ,\ C and "Delta" , the area of the triangle A B C , then 1/(p_1)+1/(p_2)-1/(p_3) is equal to s/"Delta" (b) (s-c)/"Delta" (c) (s-b)/"Delta" (d) (s-a)/"Delta"

In a triangle ABC, (s-a)/11=(s-b)/12=(s-c)/13 , then tan^2 (A//2)=

In Delta ABC, sum ( tan ""(A)/(2))/( (s-b)(s-c)) =