If a particle moving in a straight line and its distance x cms from a fixed point O on the line is given by `x=sqrt(1+t^(2))` cms, then acceleration of the particle at t sec. is

A particle is moving on a straight line and its distance x cms from a fixed point O on the line is given by x=sqrt(t^(2)+1) then the velocity of particle at t=1 is

A particle moves in a straight line, so that after t second, the distance x from a fixed point O on the line is given by x=(l-2)^(2)(t-5) . Then

The speed v of particle moving along a straight line, when it is at a distance x from a fixed point on the line is given by v^2= 108 x - 9x^2 . Then magnitude of its acceleration when it is a distance 3 metre from the fixed point is

A particle is moving in a straight line so that after t seconds its distance is s (in cms) from a fixed point on the line is given by s= f(t)=8t+t^3. Find the velocity at time t= 2sec (ii) the initial velocity can acceleration at t=2 sec