Area of the triangle having vertices `(1, 2, 3), (2, - 1, 1)` and `(1, 2, 4)` in square units is

If the area of the triangle whose vertices are A(1, 2, 3), B(2, -1, 1) and C(1, 2, -4) is lambda sq unit then (2lambda)/(sqrt(10)) must be

The area of the triangle having vertices : A (1, 1, 2), B (2, 3, 5) and C (1, 5, 5) is :

Using determinant : Find the value of t for which the area of the triangle having vertices at (-1,t),(t-2,1) and (t-2,t) is 121/2 square unit .

Find the value of m for which the area of the triangle having vertices at (-1,m) , (m-2,1) and (m-2,m) is 12(1)/(2) square units .

Find the area of the triangle ABC having vertices A(-2, 3), B(-3, 4) and C(1, 2).

What is the area of the triangle with vertices (1, 2, 3), (2, 5, -1) and (-1, 1, 2) ?

Find the area of the triangle whose vertices are A(1, 2, 3), B(2, –1, 1)and C(1, 2, –4).

The area of the triangle with vertices (1,2,3), (2,5,-1), (-1,1,2) is

Using vectors, find the area of the triangle having vertices A (1, 1, 1), B (1, 2, 3) and C (2, 3, 1).

The area of triangle whose vertices are (1,2,3), (2,5,-1) and (-1,1,2) is