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If two vertices of a triangle are (1,3) and (4,-1) and the area of triangle is 5 sq. units, then the angle at the third vertex lies in :

A

`(0,tan^-1.5/4]`

B

`(0,tan^-1.5/4)`

C

`(2tan^-1"5/4,2)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
Length of base `AB=5`
`therefore` Length of altitude `CM=2`
(`therefore` Area is 5sq.units)
Max. `angleACB=2tan^(-1).(5)/(4)`
`therefore" "angleACBin(0,2tan^(-1).(5)/(4)]`
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