A particle falls from the top of a tower and it cover `(3)/(25)` of the total height from `t=2` sec to t=4 sec. The height of the tower is:-

A body falls freely from the top of a tower. It covers 36% of the total height in the lkast second before striking the ground level. The height of the tower is

A body falls freely from the top of a tower. It covers 36% of the total height in the lkast second before striking the ground level. The height of the tower is

A body falls freely from the top of a tower. It covers 36 % of the total height in the last second before striking the ground level. The height of the tower is

A particle is dropped from the top of a tower. During its motion it covers (9)/(25) part of height of tower in the last 1 second Then find the height of tower.

A particle is dropped from the top of a tower. During its motion it covers (9)/(25) part of height of tower in the last 1 second Then find the height of tower.

A particle is dropped from the top of a tower. During its motion it covers (9)/(25) part of height of tower in the last 1 second Then find the height of tower.

A body dropped from the top of a tower covers 7/16 of the total height in the last second of its fall. The time of fall is

A body dropped from the top of a tower covers 7/16 of the total height in the last second of its fall. The time of fall is

A particle is dropped from the top of a tower. It covers 40 m in last 2s. Find the height of the tower.