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If lines 2x-3y+6=0 and kx+2y=12=0 cut th...

If lines `2x-3y+6=0` and `kx+2y=12=0` cut the coordinate axes in concyclic points, then the value of `|k|` is

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The correct Answer is:
3

`2x-3y+6=0` meets the axes at `A(-3,0)` and `B(0,2)`. `kx+2y+12=0` meets the axes at `D(0,-6)` and `C(-12//k,0)`, Points A,B.C and D will be concyclic, if
`OAxxOC=OBxxOD`
`rArr3xx(-12//k)=2xx6`
`rArrk=-3`
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