What is dimensional formulae of magnetic field (B) if F=qvB `sin theta`, where F is magnitude of force, q is charge , v is speed and B is magnetic field and `theta` is angle between velocity and magnetic field.

Options

A. `[MT^(-2)A^(-1)]`
B. `[M^(-1)T^(2)A]`
C. `[MLT^(-2)A^(-1)]`
D. `[MT^(-3)A^(1)]`

Explanation

`F=qVB sin theta`
`[B]=[(F)/(qVsin theta)]=(MLT^(-2))/(ATLT^(-1))=MT^(-2)A^(-1)`