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What is dimensional formulae of magnetic...

What is dimensional formulae of magnetic field (B) if F=qvB `sin theta`, where F is magnitude of force, q is charge , v is speed and B is magnetic field and `theta` is angle between velocity and magnetic field.

A

`[MT^(-2)A^(-1)]`

B

`[M^(-1)T^(2)A]`

C

`[MLT^(-2)A^(-1)]`

D

`[MT^(-3)A^(1)]`

Text Solution

Verified by Experts

`F=qVB sin theta`
`[B]=[(F)/(qVsin theta)]=(MLT^(-2))/(ATLT^(-1))=MT^(-2)A^(-1)`
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Knowledge Check

  • What is dimensional formulae of magnetic field (B) if F = q v B sin theta , where F is magnitude of force, q is change, v is speed and B is magnetic field and theta is angle between velocity and magnetic field.

    A
    `[M T^(-2) A^(-1)]`
    B
    `[M^(-1) T^(2) A]`
    C
    `[MLT^(-2) A^(-1)]`
    D
    `[MT^(-3)A^(1)]`

  • Dimensional formula of magnetic field is :-

    A
    `M^(1)L^(2)T^(-1)A^(-1)`
    B
    `M^(1)L^(0)T^(-2)A^(-1)`
    C
    `M^(1)L^(-2)T^(-1) A^(-1)`
    D
    `M^(1)L^(1)T^(-2)A^(-1) `

  • The dimensional formula for the magnetic field is

    A
    `[MT^(-2)A^(-1)]`
    B
    `[ML^(2)T^(-1)A^(-2)]`
    C
    `[MT^(-2)A^(-2)]`
    D
    `[MT^(-1)A^(-2)]`

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