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The angle between the vector -hati+hatj ...

The angle between the vector `-hati+hatj` and `2hati+3hatj` is :

A

`cos theta=(4)/(6)`

B

`sin theta=sqrt((25)/(26))`

C

`tan theta=sqrt(5)`

D

none of these

Text Solution

Verified by Experts

`cos theta=(veca,vecb)/(ab)=(2+3)/sqrt(2)sqrt(13)=(1)/sqrt(26)`
`sin theta=sqrt((25)/(26))`
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