A particle is projected from level ground its kineitc energy K changes due to gravity so that `K_("max")//K_("min")=9`. The ratio of the range to the maxir, un height attained during its fight is

Options

A. `sqrt(2)`
B. `4sqrt(2)`
C. 1.5
D. none

Explanation

To solve the problem, we need to find the ratio of the range to the maximum height attained by a projectile when given that the ratio of its maximum kinetic energy to minimum kinetic energy is 9.

### Step-by-step Solution:

1. **Understanding Kinetic Energy**:
The kinetic energy (K) of a particle is given by the formula:
\[
K = \frac{1}{2} mv^2
...