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A 60kg man is running on horizontal road...

A 60kg man is running on horizontal road with acceleration `2ms^(-1)` friction coefficient between foot of the man and the ground is `mu=0.4` then

A

Frictional force acting on the man is 120N

B

Frictional force acting on the man is 240N

C

Work done by friction on the man during his 2m displacement will be 240J

D

Direction of the frictional force acting on the man is opposite to his direction of motion.

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f=ma
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