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A particle is doing uniform circular mot...

A particle is doing uniform circular motion as shown. Magnitude of average velocity of the particle between points A and C will be

A

`2ms^(-1)`

B

`(2)/(5)ms^(-1)`

C

`(2)/(5)ms^(-1)`

D

`(1)/(3)ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`V_("avg")=(r)/(f)=(2r)/((pir//v))=2`
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