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A particle is projected with 20ms^(-1) a...

A particle is projected with `20ms^(-1)` at `30^(@)` above horizontal. Find ratio of maximum height to the range of the projectile.

A

`(1)/(4sqrt(3))`

B

`sqrt(3)/(4)`

C

`4sqrt(3)`

D

`(4)/sqrt(3)`

Text Solution

Verified by Experts

`H=(u^(2)sin^(2)theta)/(2g)`
`R=(v^(2)s2intheta)/(g)`
`(H)/(R)-(tan theta)/(4)`
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Knowledge Check

  • A particle is projected with velocity 20 ms ^(-1) at angle 60^@ with horizontal . The radius of curvature of trajectory , at the instant when velocity of projectile become perpendicular to velocity of projection is , (g=10 ms ^(-1))

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    `60sqrt(3)m`
    B
    `80/(sqrt(3))m`
    C
    `40sqrt(3)m`
    D
    `80/(3sqrt(3))m`
  • Two projectile are projected with the same velocity. If one is projected at an angle of 30^(@) to the horizontal. The ratio if maximum heights reached, is:

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    `1:3`
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  • A projectile is projected from the ground by making an angle of 60^@ with the horizontal. After 1 s projectile makes an angle of 30^@ with the horizontal . The maximum height attained by the projectile is (Take g=10 ms^-2)

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