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A particle start motion from rest with c...

A particle start motion from rest with constant tangential acceleration `2ms^(-2)` on a ciruclar path of radius r=8m at the time t=0. Angle between acceleration of the particle with the radiuws at the time t=2 second will be

A

`60^(@)`

B

`30^(@)`

C

`45^(@)`

D

`0^(@)`

Text Solution

Verified by Experts

`tan theta=(a_(r))/(a_(c))=(a_(r))/((v^(2)//r))=(2)/(2)=1`
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