In the system shown block is released from rest on the inclined surface of the wedge. The acceleration of the wedge will be (assume friction to be absent)

Options

A. `(g)/(5)`
B. `(g)/(4)`
C. `(g)/(3)`
D. `(g)/(2)`

Explanation

`mg sin theta`
`mg sqrt(2)`
`(N)/sqrt(2)=ma`
`(ma)/sqrt(2)-N=m(a)/sqrt(2)`
`(mg)/sqrt(2)-N=m(a)/sqrt(2)`
`(mg)/sqrt(2)-ma sqrt(2)=(mg)/sqrt(2)`
`(mg)/sqrt(2)=ma ((2+1)/sqrt(2))`
`a=(g)/(3)`