A particle of mass 4m which is at rest explodes into four equal fragments. All 4 fragments are scattered in the same horizontal plane. Three fragments are found to move with velocity V each as shown in the figure. The total energy released in the process of explosion is

Options

A. `mV^(2)(3-sqrt(2))`
B. `mv^(2)(3-sqrt(2))//2`
C. `2mV^(2)`
D. `mV^(2)(1+sqrt(2))//2`

Explanation

By conservation of momentum `vecp_(i)=0=vecpr`
`mv_(4)=mvsqrt(2)-mv`
Energy released `=KE_(r)`