An observer A is at rest in gournd frame, observer B is moving with constant another observer C is moving with constant velocity of 1m/s.

Options

A. work done by all forces (both real and pseudo) in 1 sec in frame of A is 0.5J
B. work done by all forces (both real and pseudo) in 1 sec in frame of B is 0J
C. work done by all force (both real and pseudo) in 1 sec in frame of C is -0.5J
D. change in K.E. in frame of B is zero

Explanation

`S=(1)/(2)at^(2)=(1)/(2)xx1xx1^(2)=(1)/(2)m`
`omega_(A)=1xx(1)/(2)=0.5J`
`omega_(B)=0` because in frame 1 ke is at rest.
`omega_(C)=DeltaK=0-(1)/(2)=-(1)/(2)J`
`k_(i)=(1)/(2)xx1xx1^(2)`
`k_(r)=0`