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A particle is projected at an angle of 4...

A particle is projected at an angle of `45^(@)` with the horizontal with a speed u in a uniform gravitational field, as shown in the figure. The instaneous angular speed of the particle w.r.t. Point of projection at the moment if falls at the same horizontal level equals

A

`sqrt(2g)/(u)`

B

`(g)/((sqrt(2)u)`

C

`(g)/(2sqrt(2)u)`

D

none of the above

Text Solution

Verified by Experts

`omega=((u)/sqrt(2))/((u^(2)sin90^(@))/(8))=(g)/sqrt(2u)`
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