Two balls of same mass are dropped from the same height h, on to the floor. The first ball bounces to a height h/4, after the collision `&` the second ball to a height h/16. The impulse applied by the first `&` second ball on the floor are `I_(1)` and `I_(2)` respectively. Then

Options

A. `5I_(1)=6I_(2)`
B. `6I_(1)=5I_(2)`
C. `I_(1)=2I_(2)`
D. `I_(2)=2I_(1)`

Explanation

`(I_(2))/(I_(2))=(msqrt(2gh)+msqrt(2gh//4))/(msqrt(2gh)+msqrt(2gh//16))`
`=(1(1)/(2))/(1+(1)/(4))=((3)/(2))/((3)/(4))=(6)/(5)`