Two blocks of mass 2m and m slide down the slope AB having same friction coefficient Then:

Options

A. the heavier mass reaches the bottom in a shorter time
B. both the masses have the same kinetic energy on arriving at B
C. the heavier mass has twice the momentum than that of the other when reaching B
D. the lighter mass reaches the bottom in a shorter time

Explanation

`a=g sin theta-mug cos theta` is same for (1) and (2) both will read bottom with same speed
`u^(2)=0+2as`
`K_(1)=(1)/(2)(2m)v_(t)^(2)`
`K_(2)=(1)/(2)(m)v_(2)^(2)`
`k_(1)cancel=k_(2)`
`p_(1)=2mv_(1),p_(2)=mv_(2)`
`p_(1)=2p_(2)`