A ring of radius 1m is in xy-plane with centre at the origin. In each of option below, the moment of inertia of the ring about the line is calculated. In which case does the ring have same of inertia as that about z-axis.

Options

A. `y=gamma`
B. `x+y=(1)/sqrt(2)`
C. `-x-y=(1)/sqrt(2)`
D. `x=(1)/sqrt(2)`

Explanation

If axis lies inplane of ring/lies at a distance d from its centre.
`I_(d)=(MR^(2))/(2)+Md^(2)=MR^(2)`
`rArr d=(R)/sqrt(2)=(1)/sqrt(2)m`
`therefore` distance of line from centre should be `(1)/sqrt(2)`