A uniform cylinder of radius R originally had weight of 80N. It weigths 65N, after an off axis cylinderical hoole at `(2R)/(3)` was drilled through n.
The axis of the two cylinders are parallel and at same height A force T is applied to the top of the cylinder horizontally to keep the cylinder at rest about the axis of the original cylinder passing through O. The value of force should be

Options

A. 1N
B. 3N
C. 5N
D. 10N

Explanation

`15xx(2R)/(3)=65x`
`TR=65x=15xx(2R)/(3)`
`T=10` N